Question

みー

わかりやすい途中式を書いてください

sina
1
(3) tana =
2√2
1
sinß
÷
=
tan ß
=
=
Cosa 3
3
2√2
cosp
√5
3
√5
=
3
=
2
1
√5
tana +tan ẞ
2√2
2
よって
tan (a+ẞ)
=
1- tanatan ẞ
√5
1
2√2
2
1-10
2√2
)+(1.
√5
1-√10
4√√2+5
4√√√2
2√2
4√2
2 (1-√10)
=
=
2(1-10)(4√√2-√√√5)
4√√2+√5 (4√2+√5)(4√2−√5)
2(92-95) 2√2-25
27
=
3