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x^3+-3x^2+x+2=0 の解がα、β、γ
→x^3-(α+β+γ)x^2+(αβ+αγ+βγ)x-αβγなので、
α+β+γ=3
αβ+αγ+βγ=1
αβγ=2
(α+1)(β+1)(γ+1)
=αβγ+(αβ+αγ+βγ)+(α+β+γ)+1
=3+1+2+1
=7
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