✨ Best Answer ✨
sin2α=2sinαcosα
cos2α=cos2α–sin2α=2cos2α–1=1–2sin2α
tan2α=2tanα1–tan2α
sin2α=1–cos2α2
cos2α=1+cos2α2
✨ Best Answer ✨
sin2α=2sinαcosα
cos2α=cos2α–sin2α=2cos2α–1=1–2sin2α
tan2α=2tanα1–tan2α
sin2α=1–cos2α2
cos2α=1+cos2α2
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