Question

りと

わかりやすく説明お願いします🙇‍♀️

0≦0 <2π のとき,次の方程式、不等式を解け。 [282~284]
π
282 (1) sin(0.
sin (0-347) --- 12/1
=
*(3) tan (0-
(0-)>1
6
(D)
(*(2)
π
*(2) cos 20+.
Os (26
√3
=
(E)
3
2
(4) sin (20+7) ≤ -1/1/00
6

Answer 1

BaSO4

(1)
0<=θ<=2π
-π/3<=θ-π/3<=2π-π/3
θ-π/3=Xとおくと
sinX=-1/2
X=-π/6,7π/6←範囲が-π/3〜5π/3なことに注意
θ=-π/6+π/3,7π/6+π/3
=π/6,3π/2

(2)〜(4)も大体同じ