2x+1=tとおくと
x=(t-1)/2
dx=dt
より、
与式=∮3(t-1)/2t dt
=3/2∮(t-1)/t dt
=3/2∮ {1-1/t}dt
=3/2( t-logt)+C’
=3/2 {2x+1-log(2x+1)}+C’
=3x+3/2-3/2log(2x+1)+C’
=3x-3/2log(2x+1)+C (C,C'は積分定数)
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