✨ Best Answer ✨
tan(π/2)→∞なので違います。
sin(φ-π/2)
tan(φ-π/2) = ─────
cos(φ-π/2)
-cosφ
tan(φ-π/2) = ───
sinφ
1
tan(φ-π/2) = - ───
tanφ
✨ Best Answer ✨
tan(π/2)→∞なので違います。
sin(φ-π/2)
tan(φ-π/2) = ─────
cos(φ-π/2)
-cosφ
tan(φ-π/2) = ───
sinφ
1
tan(φ-π/2) = - ───
tanφ
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ありがとうございます!